09
January ÒÑÖªm+1/m=¡Ì5£¬Çóm-1/mµÄÖµ
ÒÑÖªm+1/m=¡Ì5£¬Çóm-1/mµÄÖµ
ÒÑÖªm+1/m=¡Ì5
(m+1/m)^2=5,m^2+(1/m)^2=3,m^2+(1/m)^2-2=3-2
(m-1/m)^2=1,m-1/m=+1,-1
×î¼Ñ´ð°¸ - ÓÉͶƱÕß2008-09-13 16:22:03Ñ¡³ö
ÒÑÖªm+1/m=¡Ì5£¬Çóm-1/mµÄÖµ
½â£º½«m+1/m=¡Ì5µÄÁ½±ßƽ·½µÃ£º
m +1/m =3
¹Ê£¨m-1/m) =m -2+1/m =3-2=1
¡àm-1/m=¡À1.
3-¡Ì5/2
1-¡Ì5/2
1-4(2¡À¡Ì2)
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